(x-1)(x-5)=x^2+4x

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Solution for (x-1)(x-5)=x^2+4x equation: 



(x-1)(x-5)=x^2+4x

We move all terms to the left:

(x-1)(x-5)-(x^2+4x)=0

We get rid of parentheses

-x^2+(x-1)(x-5)-4x=0

We multiply parentheses ..

-x^2+(+x^2-5x-1x+5)-4x=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-5x-1x+5)-4x=0

We get rid of parentheses

-1x^2+x^2-5x-1x-4x+5=0

We add all the numbers together, and all the variables

-10x+5=0

We move all terms containing x to the left, all other terms to the right

-10x=-5

x=-5/-10

x=1/2

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